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Chi-Square Tests

Chi-Square tests are non-parametric statistical tests used to examine the relationships between categorical variables. They are widely used in situations where you want to test the association or independence between two or more categorical variables or assess how well an observed distribution fits an expected distribution. This article covers the two main types of Chi-Square tests: the goodness-of-fit test and the test of independence, along with detailed examples and interpretations.

What is a Chi-Square Test?

A Chi-Square test is a statistical test that measures how expected counts compare to observed counts in categorical data. The test statistic is calculated by summing the squared difference between observed and expected counts, divided by the expected counts. The formula for the Chi-Square statistic (χ2\chi^2) is:

χ2=(OiEi)2Ei\chi^2 = \sum \frac{(O_i - E_i)^2}{E_i}

Where:

  • OiO_i is the observed frequency in each category.
  • EiE_i is the expected frequency in each category.

Types of Chi-Square Tests

  1. Goodness-of-Fit Test: Used to determine if a sample matches an expected distribution.
  2. Test of Independence: Used to determine if there is an association between two categorical variables.

Goodness-of-Fit Test

The Goodness-of-Fit test is used to compare an observed distribution to an expected distribution. It helps determine whether the observed data follows a specific distribution.

When to Use the Goodness-of-Fit Test

  • You want to test if a sample of categorical data matches an expected distribution (e.g., testing if a die is fair).
  • The categories are mutually exclusive, and the observations are independent.

Hypotheses

  • Null Hypothesis (H0H_0): The observed frequencies match the expected frequencies.
  • Alternative Hypothesis (H1H_1): The observed frequencies do not match the expected frequencies.

Example: Testing the Fairness of a Die

Suppose you roll a six-sided die 60 times and record the results. You expect each number (1 through 6) to appear 10 times if the die is fair. The observed results are as follows:

OutcomeObserved (O)Expected (E)
1810
21210
3910
41110
51310
6710

Calculating the Chi-Square Statistic

  1. Calculate the Chi-Square statistic using the formula:
χ2=(OiEi)2Ei\chi^2 = \sum \frac{(O_i - E_i)^2}{E_i}

For the example:

χ2=(810)210+(1210)210+(910)210+(1110)210+(1310)210+(710)210\chi^2 = \frac{(8 - 10)^2}{10} + \frac{(12 - 10)^2}{10} + \frac{(9 - 10)^2}{10} + \frac{(11 - 10)^2}{10} + \frac{(13 - 10)^2}{10} + \frac{(7 - 10)^2}{10} χ2=410+410+110+110+910+910=2.8\chi^2 = \frac{4}{10} + \frac{4}{10} + \frac{1}{10} + \frac{1}{10} + \frac{9}{10} + \frac{9}{10} = 2.8
  1. Determine the degrees of freedom (df):
df=Number of categories1=61=5\text{df} = \text{Number of categories} - 1 = 6 - 1 = 5
  1. Compare the calculated χ2\chi^2 value to the critical value from the Chi-Square distribution table at the desired significance level (e.g., α=0.05\alpha = 0.05).

Interpreting the Results

If the calculated χ2\chi^2 value exceeds the critical value from the table, you reject the null hypothesis, indicating that the die is not fair. If the χ2\chi^2 value is less than the critical value, you fail to reject the null hypothesis, suggesting that the observed distribution matches the expected distribution.

Test of Independence

The Chi-Square Test of Independence is used to determine if there is a significant association between two categorical variables. It tests whether the distribution of one variable is independent of the distribution of another.

When to Use the Test of Independence

  • You have two categorical variables and want to test if they are independent.
  • The data are arranged in a contingency table.

Hypotheses

  • Null Hypothesis (H0H_0): The variables are independent (no association).
  • Alternative Hypothesis (H1H_1): The variables are not independent (there is an association).

Example: Testing the Association Between Gender and Voting Preference

Suppose you conduct a survey to test whether gender is associated with voting preference. The results are organized in a contingency table:

Prefer Candidate APrefer Candidate BTotal
Male302050
Female252550
Total5545100

Calculating the Chi-Square Statistic

  1. Calculate the expected frequencies for each cell:
Eij=Row Total×Column TotalGrand TotalE_{ij} = \frac{\text{Row Total} \times \text{Column Total}}{\text{Grand Total}}

For the first cell (Male, Prefer Candidate A):

E11=50×55100=27.5E_{11} = \frac{50 \times 55}{100} = 27.5

Repeat for each cell to get the full expected table:

Prefer Candidate APrefer Candidate B
Male27.522.5
Female27.522.5
  1. Calculate the Chi-Square statistic:
χ2=(OijEij)2Eij\chi^2 = \sum \frac{(O_{ij} - E_{ij})^2}{E_{ij}}

For the example:

χ2=(3027.5)227.5+(2022.5)222.5+(2527.5)227.5+(2522.5)222.5\chi^2 = \frac{(30 - 27.5)^2}{27.5} + \frac{(20 - 22.5)^2}{22.5} + \frac{(25 - 27.5)^2}{27.5} + \frac{(25 - 22.5)^2}{22.5} χ2=6.2527.5+6.2522.5+6.2527.5+6.2522.5=0.227+0.278+0.227+0.278=1.01\chi^2 = \frac{6.25}{27.5} + \frac{6.25}{22.5} + \frac{6.25}{27.5} + \frac{6.25}{22.5} = 0.227 + 0.278 + 0.227 + 0.278 = 1.01
  1. Determine the degrees of freedom:
df=(Number of rows1)×(Number of columns1)=(21)×(21)=1\text{df} = (\text{Number of rows} - 1) \times (\text{Number of columns} - 1) = (2 - 1) \times (2 - 1) = 1
  1. Compare the calculated χ2\chi^2 value to the critical value from the Chi-Square distribution table at the desired significance level (e.g., α=0.05\alpha = 0.05).

Interpreting the Results

If the calculated χ2\chi^2 value exceeds the critical value, you reject the null hypothesis, indicating that there is a significant association between gender and voting preference. If the χ2\chi^2 value is less than the critical value, you fail to reject the null hypothesis, suggesting that the two variables are independent.

Assumptions of Chi-Square Tests

For Chi-Square tests to be valid, certain assumptions must be met:

1. Independence of Observations

The observations should be independent of each other. This means that the data collected for one observation should not influence the data collected for another.

2. Expected Frequency

In each cell of the contingency table, the expected frequency should be at least 5. If the expected frequency is less than 5 in any cell, the Chi-Square test may not be reliable. In such cases, Fisher's Exact Test may be a better alternative.

3. Categorical Data

Chi-Square tests are only applicable to categorical data. The data should be counts or frequencies, not continuous measurements.

Limitations of Chi-Square Tests

1. Sensitivity to Sample Size

Chi-Square tests can be sensitive to sample size. With a large sample, even small differences can become statistically significant, which may not be practically meaningful. Conversely, with a small sample, large differences may not reach statistical significance.

2. Only Tests Association, Not Causation

Chi-Square tests can indicate whether two variables are associated, but they do not provide information about causality.

3. Assumption Violations

Violations of the assumptions (e.g., low expected frequencies, non-independence) can lead to invalid results. It's important to check assumptions before interpreting the results.

Conclusion

Chi-Square tests are essential tools for analyzing categorical data and testing hypotheses about distributions and associations. By understanding how to perform and interpret both the goodness-of-fit test and the test of independence, you can gain valuable insights into the relationships between categorical variables in your data. However, it's crucial to ensure that the assumptions of the Chi-Square test are met to avoid incorrect conclusions.